25y^2-9=(5y+3)(5y-3)

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Solution for 25y^2-9=(5y+3)(5y-3) equation: 



25y^2-9=(5y+3)(5y-3)

We move all terms to the left:

25y^2-9-((5y+3)(5y-3))=0

We use the square of the difference formula

25y^2+25y^2+9-9=0

We add all the numbers together, and all the variables

50y^2=0

a = 50; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·50·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{100}=0$

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